LeetCode 961: N-Repeated Element in Size 2N Array#114
Conversation
📝 WalkthroughWalkthroughAdds a new LeetCode solution for problem 961 and corresponding tests. The Solution.repeatedNTimes method scans the list and returns the first value seen twice using a hash-based container. Changes
Estimated code review effort🎯 2 (Simple) | ⏱️ ~10 minutes Poem
Pre-merge checks and finishing touches❌ Failed checks (1 warning)
✅ Passed checks (2 passed)
✨ Finishing touches
Thanks for using CodeRabbit! It's free for OSS, and your support helps us grow. If you like it, consider giving us a shout-out. Comment |
There was a problem hiding this comment.
Actionable comments posted: 1
🧹 Nitpick comments (1)
LeetCode/easy/n_repeated_element_961.py (1)
6-12: Consider using a set for cleaner, more idiomatic code.The algorithm is correct and efficient. However, since the stored value in
seen_hashis never used, a set would be more appropriate and memory-efficient than a dictionary.🔎 Proposed refactor using set
def repeatedNTimes(self, nums: List[int]) -> int: - seen_hash = {} # this can solved with set as well + seen = set() for num in nums: - if num in seen_hash: + if num in seen: return num - seen_hash[num] = 1 + seen.add(num)
📜 Review details
Configuration used: defaults
Review profile: CHILL
Plan: Pro
📒 Files selected for processing (2)
LeetCode/easy/n_repeated_element_961.pytests/test_leetcode_easy.py
🧰 Additional context used
🧬 Code graph analysis (1)
tests/test_leetcode_easy.py (1)
LeetCode/easy/n_repeated_element_961.py (2)
Solution(5-12)repeatedNTimes(6-12)
🔇 Additional comments (1)
tests/test_leetcode_easy.py (1)
137-160: LGTM!The test cases are comprehensive and cover all the key scenarios including edge cases (minimum size array, all elements the same, different positions of repeated elements, and various array sizes). The test structure follows pytest conventions correctly.
|
|
||
| class Solution: | ||
| def repeatedNTimes(self, nums: List[int]) -> int: | ||
| seen_hash = {} # this can solved with set as well |
There was a problem hiding this comment.
Fix grammatical error in comment.
The comment has a grammar issue: "this can solved" should be "this can be solved".
🔎 Proposed fix
- seen_hash = {} # this can solved with set as well
+ seen_hash = {} # this can be solved with set as well📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
| seen_hash = {} # this can solved with set as well | |
| seen_hash = {} # this can be solved with set as well |
🤖 Prompt for AI Agents
In LeetCode/easy/n_repeated_element_961.py around line 7, the inline comment
reads "this can solved with set as well" which is grammatically incorrect;
update it to "this can be solved with a set as well" (or "this can also be
solved with a set") to correct grammar and improve clarity.
|
@coderabbitai generate docstrings |
✅ Actions performedInitiated docstring generation; will generate only if new commits exist. |
|
Note Docstrings generation - SUCCESS |
Docstrings generation was requested by @WazedKhan. * #114 (comment) The following files were modified: * `LeetCode/easy/n_repeated_element_961.py`
📝 Add docstrings to `961-n-repeated-element`
There was a problem hiding this comment.
Actionable comments posted: 0
♻️ Duplicate comments (1)
LeetCode/easy/n_repeated_element_961.py (1)
16-16: Fix grammatical error in comment.The grammatical error "this can solved" was already flagged in a previous review and should be corrected to "this can be solved with a set as well".
🧹 Nitpick comments (1)
LeetCode/easy/n_repeated_element_961.py (1)
16-21: Consider using a set instead of a dictionary.The implementation correctly identifies the repeated element. However, since you only check for presence and never use the dictionary values, a set would be more idiomatic and slightly more efficient.
🔎 Proposed refactor using a set
- seen_hash = {} # this can solved with set as well + seen = set() for num in nums: - if num in seen_hash: + if num in seen: return num - seen_hash[num] = 1 + seen.add(num)
📜 Review details
Configuration used: defaults
Review profile: CHILL
Plan: Pro
📒 Files selected for processing (1)
LeetCode/easy/n_repeated_element_961.py
🔇 Additional comments (1)
LeetCode/easy/n_repeated_element_961.py (1)
5-15: LGTM! Well-documented method signature.The class structure, method signature with type hints, and auto-generated docstring are all clear and follow Python conventions.
Summary by CodeRabbit
New Features
Tests
✏️ Tip: You can customize this high-level summary in your review settings.