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Problem17.py
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60 lines (55 loc) · 2.06 KB
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"""
If the numbers 1 to 5 are written out in words: one, two, three, four, five,
then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
If all the numbers from 1 to 1000 (one thousand) inclusive were written out
in words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example,342
(three hundred and forty-two) contains 23 letters and 115
(one hundred and fifteen) contains 20 letters.The use of "and" when writing
out numbers is in compliance with British usage.
"""
numbers = ["one", "two", "three", "four", "five", "six", "seven", "eight",
"nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen",
"seventeen", "eighteen", "nineteen"]
def lessThanHundred(i):
if(i < 20):
return numbers[i-1]
elif(i >= 20 and i < 30):
if(i==20): return "twenty"
return "twenty " + numbers[i % 10 -1]
elif(i >= 30 and i < 40):
if(i==30): return "thirty"
return "thirty " + numbers[i % 10 -1]
elif(i >= 40 and i < 50):
if(i==40): return "forty"
return "forty " + numbers[i % 10 -1]
elif(i >= 50 and i < 60):
if(i==50): return "fifty"
return "fifty " + numbers[i % 10 -1]
elif(i >= 60 and i < 70):
if(i==60): return "sixty"
return "sixty " + numbers[i % 10 -1]
elif(i >= 70 and i < 80):
if(i==70): return "seventy"
return "seventy " + numbers[i % 10 -1]
elif(i >= 80 and i < 90):
if(i==80): return "eighty"
return "eighty " + numbers[i % 10 -1]
elif(i >= 90 and i < 100):
if(i==90): return "ninety"
return "ninety " + numbers[i % 10 -1]
def numberString(i):
if(i < 100):
return lessThanHundred(i)
elif(i < 1000):
string = numbers[i // 100 -1] + " hundred"
if(i % 100 > 0):
string += " and " + lessThanHundred(i % 100)
return string
else:
return "one thousand"
sum = 0
for i in range(1,1001):
print(i, ": ", numberString(i), len(numberString(i).replace(" ", "")))
sum += len(numberString(i).replace(" ", ""))
print(sum)