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2322.cpp
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67 lines (62 loc) · 2.28 KB
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class Solution {
public:
int dfs(int curr, vector<bool>& visited, vector<int>& nums, vector<vector<int>>& adj, vector<int>& nodeXor, vector<int>& parents, vector<vector<bool>>& isChild, vector<vector<int>>& pcEdges) {
visited[curr] = true;
int res = 0;
res ^= nums[curr];
for (auto& p : parents) isChild[p][curr] = true;
parents.push_back(curr);
for (auto& neighbor : adj[curr]) {
if (!visited[neighbor]) {
pcEdges.push_back({curr, neighbor});
res ^= dfs(neighbor, visited, nums, adj, nodeXor, parents, isChild, pcEdges);
}
}
parents.pop_back();
nodeXor[curr] = res;
return res;
}
int minimumScore(vector<int>& nums, vector<vector<int>>& edges) {
int n = nums.size();
vector<vector<int>> adj(n);
vector<int> nodeXor(n, 0);
vector<bool> visited(n, false);
vector<int> parents;
vector<vector<bool>> isChild(n, vector<bool>(n, false));
vector<vector<int>> pcEdges;
for (auto& edge : edges) {
adj[edge[0]].push_back(edge[1]);
adj[edge[1]].push_back(edge[0]);
}
dfs(0, visited, nums, adj, nodeXor, parents, isChild, pcEdges);
int res = INT_MAX;
int m = pcEdges.size();
for (int i = 0; i < m; ++i) {
for (int j = i + 1; j < m; ++j) {
int a = pcEdges[i][1];
int b = pcEdges[j][1];
int xa, xb;
int xc = nodeXor[0];
// b is a's child
if (isChild[a][b]) {
xb = nodeXor[b];
xa = nodeXor[a] ^ nodeXor[b];
xc = xc ^ nodeXor[a];
}
// a is b's child
else if (isChild[b][a]) {
xa = nodeXor[a];
xb = nodeXor[b] ^ nodeXor[a];
xc = xc ^ nodeXor[b];
}
else {
xa = nodeXor[a];
xb = nodeXor[b];
xc = xc ^ xa ^ xb;
}
res = min(res, max({xa, xb, xc}) - min({xa, xb, xc}));
}
}
return res;
}
};